Earthwork calculations

1. As shown below, bottom width 1.2m, deepened 1.6m, for the three types of soil
soil, digging grooves on both sides of artificial demand side slope of the relaxation of the number?
】 【solution is known: K = 0.33, h = 1.6m, then:
each side of the cut slope width b = 1.6 × 0.33m = 0.53m
to bottom width of 1.2 m, after the upper opening width grading: (1.2 +0.53 × 2) m = 2.26m
2. a place as shown by Excavation, hold slope, no face, three types of soil. Calculate the integrated base price.

】 【solution tank wall to project the amount of = 1.05 × 1.4 × (21.6 +7.2) × 2m3 = 84.67m3
tank interior to project the amount of = 0.9 × 1.4 × (7.2-1.05) × 3m3 = 23.25m3
geosynclinal pile quantities with = 0.125 × 1.4 × 1.2 × 6m2 = 1.26m3
Total = (84.67 +23.25 +1.26) m3 = 109.18m3
fixed set of subheadings 1-33 ; 1453.23/100m2 × 767.16 = 11148.60 (yuan)
digging slot strip foundation for the building, laying underground pipe in a trench, communication cables and drains, etc excavators
process. Excavation and digging the pit was the end of the size difference, they apply to the construction of the basement, full house foundation, an independent foundation, foundation and other excavation equipment.
3. the basis of a building as shown below, three types of soil, indoor and outdoor height of 0.3 meters.
calculation: (1) manual digging trough integrated base price; (2) the volume of brick base and its comprehensive base price.

volume = base top width of brick base × (design height + fold increase height) × base length (www.129yy.com million million space)
big release foot brick base is to big put discount foot height section layer, the thickness of the wall at different, folded height. Fold increase height of the table below. Table 1 Standard
put foot high brick base foldable big plus height (unit: m)

】 【Solutions (1) Calculate the volume of digging trough: < br> geosyncline geosyncline net length = length + interior wall to the center line of a long trough
; = {[5.00-(0.45 +0.3 +0.1) × 2] + [7 +5 +7 +5]} m = 27.30m
to tank volume = (0.9 +2 × 0.3 +2 × 0.1) × 1.0 × 27.30m3 = 46.41m3
fixed set of subheadings 1-33 1453.23/100m2 × 46.41 = 674.44 (dollars)
(2) calculated based on the size of bricks:
; the project is put foot high brick base Large, placed three feet, bricks, check off the table height was 0.259. Cross-sectional area of ​​brick: (0.259 +1.2) × 0.365 = 0.5325 (m2)
of brick in the wall length = length + outer wall net basis based on the center line of a long
= {(5.0-0.37) + (7 +5 +7 +5)} m = 28.63m
brick base volume basis = basis of cross-sectional area × length = 0.5325 × 28.63m3 = 15.25m3
fixed set of subheadings 3-1 1461.08/10m2 × 15.25 = 2228.15 (RMB)
4. a the basis of the building as shown below, three types of soil, calculation of quantities of artificial digging trough and its comprehensive base price.

【Solutions To calculate the axis of the order by number, from left to right, bottom-up. Based on the merger of the same width.
11,12-axis: the depth of the outdoor ground to the bottom × width × length
= (0.98-0.3) × (0.92 +0.3 × 2) × 9 × 2m3 = 25.99m3
①, ② axis: (0.98-0.3) × (0.92 +0.3 × 2) × (9-0.68) × 2m3 = 24.03m3
③, ④, ⑤, ⑧, ⑨, ⑩ axis:
(0.98-0.3) × (0.92 +0.3 × 2) × (7-0.68-0.3 × 2) × 6m3 = 49.56m3
⑥, ⑦ axis: (0.98-0.3) × (0. 92 +0.3 × 2) × (8.5-0.68-0.3 × 2) × 2m3 = 20.85m3
A, B, C, D, E, F-axis: (0.84-0.3) × (0.68 +0.3 × 2) × [39.6 × 2 + (3.6-0.92)] m3 = 84.89m3
digging trough quantities = (25.99 +24.03 +49.56 +20.85 +84.89) m3 = m3
fixed set of subheadings 1-33 1453.23 / 100m2 × 205.32 = 2983.77 (www.129yy.com million million space)
5. digging a groove cut slope construction as shown below, three types of soil, to calculate the integrated base price.
】 【solution quantities = (1.5 +1.5 +0.594 × 2) × 1.8 ÷ 2 × [(21 ten 12 +15) × 2 + (15-1.5)] m2 = 412.73m2
; set of fixed subheadings 1-34 1530.46 / m2 × 412.73 = 6316.67 (RMB)

6. As shown, seeking support retaining hand-dug trench Board Earthwork (Type II soil) and its comprehensive base price.
】 【Solutions (1) excavation quantities:
(1.4 +0.1 × 2 +0.15 × 2) × 1.5 × (20 +10) × 2m3 = 1.9 × 1.5 × 60m3 = 171.00m3
subheadings 1-29 scale for (767.16 × 1.1) / 100m2 × 171.00 = 1443.03 (RMB)
(2) retaining plate Quantity: 1.5 × 2 × (20 +10) × 2m2 = 3 × 60m2 = 180m2
fixed set of subheadings 1-62 1948.57/100m2 × 180 = 3507.43 (RMB)
manual digging trough fixed, the general category and excavation depth of the soil by a fixed item, works including excavation, loading soil, throwing soil on the tank outside the edge of 1m, repair tank wall, bottom, in the preparation of project budget, there is no geological data, but also difficult to be sure
Zanan dry soil when the soil type, soil Kennedy calculation. When the final account to be adjusted according to actual soil type.

7. digging a square pit as shown, face width of 150, put the slope coefficient of 1:0.25, four types of soil. Find the amount of its engineering and its comprehensive base price.

】 【solutions hold square pit slope formula: V = abH, pit depth 2.8m, slope coefficient of 0.25 release
V = (2.8 +0.15 × 2 +0.25 × 2.8) 2 × 2.8 +1 / 3 × 0.252 × 2.83m3 = 40.89m3
fixed set of subheadings 1-51 2567.43/100m2 × 40.89 = 1049.81 (RMB)
8. As shown, find the Work and General base price. Soil for the three types of soil, a cushion, put a foundation trench slope, slope 0.33.

Solutions】 【Quantity = (2 +0.15 × 2 +2 +0.15 × 2 +1.9 × 0.33 × 2) × 1.9 ÷ 2 × [(9 +7.5 +7.5 +8.4) × 2 + (8.4-2-0.15 × 2) × 2] m3 = 428.22m3
fixed set of subheadings 1-34 1530.46/100m2 × 428.22 = 6553.74 (RMB)
9. of a building based on plans, sections, as shown. Known outdoor design floor the following quantities: cushion volume 2.4m2, brick base volume 16.24m3. Find the level of the building site, excavation, backfill, backfill the heart room, more than the amount of land transport projects (without regard to the transport Watian earth), artificial soil loading dump trucks of earth, distance 300m. Diagram dimensions are in mm of dollars. Grading coefficient K = 0.33, face width c = 300mm.

Solutions】 【flat ground area of ​​F = (a +4) × (6 +4) = (3.2 × 2 +0.24 +4) × (6 +0.24 +4) m2 = 108.95m2
fixed set of subheadings 1-56 218.44/100m2 × 108.95 = 237.99 (dollars)
digging tank volume (by cushion placed under the surface slope calculated)
V1 = H (a +2 c + K × H) L
= 1.5 × (0.8 +2 × 0.3 +0.33 × 1.5) × [(6.4 +6) × 2 + (6-0.4 × 2-0.3 × 2)] m3 = 83.50m3
sets Fixed subheadings 1-33 1453.23/100 m3 × 83.50 = 1213.45 (RMB)
foundation excavation backfill volume
V2 = volume of the outdoor terrace of a masonry laid the following amount = (83.50-2.4- 16.24) m3 = 64.86m3
fixed set of subheadings 1-54 680.64/100m3 × 64.86 = 441.46 (dollars)
Housing heart backfill volume
V3 = indoor surface area × h = (3.2 -0.24) × (6-0.24) × 2 × 0.27m3 = 9.21m3
fixed set of subheadings 1-54 680.64/100 m3 × 9.21 = 62.69 (dollars)
soil transport volume of more than
V4 = volume of excavation backfill a volume basis - Housing heart backfill volume = (83.50-64.86-9.21) m3 = 9.43m3
fixed set of subheadings 1-136 1272.04/100 m3 × 9.43 = 117.15 (yuan)
10. a basic structure for the full house foundations, foundation cushion for the plain concrete, the outside line length and width dimensions of the direction of 8.04m and 5.64m, cushion thickness of 20cm, the top surface elevation of a cushion 4.55 m, outdoor floor elevation of 0.65m, often underground water level elevation-3.50m, where the soil type for the three types of soil, artificial excavation, calculate excavation quantities.

】 【solution shown Foundation, foundation often buried to the ground water level below the pit with dry, wet soil, should be calculated separately:
(1) wet and dry soil dug total:
look-up table was k = 0.33, k2h3 = × 0.332 × 3.93 = 2.15, set cushion part of the earthwork for the V1, the amount of cushion for the excavation of more than V2, the total earth as V0, then V0 = Vl + V2 = a × b × 0.2 + (a + k × h) (b + k × h) × h + k2h3
= (8.04 × 5.64 × 0.2 +9.327 × 6.927 × 3.9 +2.15) m3 = (9.07 +254.12) m3 < br> = 263.19m3
(2) cut the amount of wet soil:
click the image, put the wet slope part of the digging depth of 1.05m, the report k2h3 = 0.042, wet set amount of V3, the
V3 = V1 + (8.04 +0.33 × 1.05) (5.64 +0.33 × 1.05) × 1.05 +0.042
= (907 +8.387 × 5.987 × 1.05 +0.042) m3 = 61.84m3
1-5 for a fixed subdirectory (1111.76 +668.01 × 0.18) / 100m2 × 61.84 = 761.87 (dollars)
(3) the amount of dry soil dug V4:
V4 = Vo-V3 = (263.19-61.84) m3 = 201.35m3 fixed set of subheadings 1-5 1111.76/100m2